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6x^2-245x+1225=0
a = 6; b = -245; c = +1225;
Δ = b2-4ac
Δ = -2452-4·6·1225
Δ = 30625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30625}=175$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-245)-175}{2*6}=\frac{70}{12} =5+5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-245)+175}{2*6}=\frac{420}{12} =35 $
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